3Cos^2(x)+5cosx+1=0

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Solution for 3Cos^2(x)+5cosx+1=0 equation:


Simplifying
3Cos2(x) + 5cosx + 1 = 0

Multiply os2C * x
3os2xC + 5cosx + 1 = 0

Reorder the terms:
1 + 5cosx + 3os2xC = 0

Solving
1 + 5cosx + 3os2xC = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 5cosx + -1 + 3os2xC = 0 + -1

Reorder the terms:
1 + -1 + 5cosx + 3os2xC = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 5cosx + 3os2xC = 0 + -1
5cosx + 3os2xC = 0 + -1

Combine like terms: 0 + -1 = -1
5cosx + 3os2xC = -1

Add '-3os2xC' to each side of the equation.
5cosx + 3os2xC + -3os2xC = -1 + -3os2xC

Combine like terms: 3os2xC + -3os2xC = 0
5cosx + 0 = -1 + -3os2xC
5cosx = -1 + -3os2xC

Divide each side by '5osx'.
c = -0.2o-1s-1x-1 + -0.6sC

Simplifying
c = -0.2o-1s-1x-1 + -0.6sC

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